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MCQs 1:

What is the process of converting alternating current into direct current known as?





Topic: Current Conversion in Electrical Systems

Correct Answer: C) Rectification

Short Hint:
  • The process of conversion from alternating current (AC) to direct current (DC) is known as rectification.
  • Therefore, the correct answer is C, "Rectification."

MCQs 2:

In a half or full wave rectifier, how does the peak inverse voltage of the rectifier compare to the input voltage?





Topic: Rectification Process in Electrical Engineering

Correct Answer: B) It's less than the input voltage.

Short Hint:
  • The peak inverse voltage of a rectifier, whether half-wave or full-wave, is always less than the input voltage.
  • This reduction in voltage is primarily due to the presence of diodes, which cut down the output voltage by approximately 0.7V.
  • Therefore, the correct answer is B, "It's less than the input voltage."

MCQs 3:

Given a circuit with an input of an alternating sinusoidal wave, what would be the output?





Topic: Functionality of Electrical Circuits

Correct Answer: D) IV

Short Hint:
  • The provided circuit is a full wave rectifier, which converts an AC input to a DC output.
  • The presence of a capacitor at the end of the circuit acts as a filter, smoothing out the waveform to produce the curve shown in IV.
  • Hence, the correct answer is D, "IV."

Question 4:

If a half-wave rectifier has an input frequency of n Hz AC, what would its output be?





Topic: Fundamental Concepts in AC-DC Conversion

Correct Answer: C) n Hz pulsating DC

Short Hint:
  • A pulsating DC is a waveform that maintains a constant direction but may change in magnitude.
  • For a half-wave rectifier with an input frequency of n Hz AC, the output frequency remains the same, producing an n Hz pulsating DC.
  • Therefore, the correct answer is C, "n Hz pulsating DC."

Question 5:

What would be the state of resistance in an ideal diode when applied in reverse bias?





Topic: Characteristics of Ideal Diodes

Correct Answer: D) Infinite resistance

Short Hint:
  • An ideal diode is a conceptual model that simplifies the behavior of real diodes.
  • When a diode is reverse-biased, it ideally blocks all current flow.
  • This can be interpreted as the diode presenting infinite resistance to the circuit.
  • Therefore, the correct answer is D, "Infinite resistance."

Question 6:

For a full wave rectifier with an input frequency of 50Hz, what is the frequency of the ripple in the output?





Topic: Full Wave Rectification Process

Correct Answer: C) 100Hz

Short Hint:
  • Full wave rectification is a process where both half cycles (positive and negative) of the AC input signal are allowed to pass through.
  • The frequency of the ripple in the output is twice the input frequency.
  • For an input frequency of 50Hz, the ripple frequency would be 2*50 = 100Hz.
  • Hence, the correct answer is C, "100Hz."

Question 7:

What is the required number of diodes for a bridge rectifier?





Topic: Structure of Bridge Rectifiers

Correct Answer: D) 4

Short Hint:
  • A bridge rectifier is a circuit used to convert AC to DC and requires four or more diodes.
  • It ensures that the output polarity is the same for any input polarity.
  • So, the correct answer is D, "4."

Question 8:

Assuming a half-wave rectifier and a full-wave rectifier both have an input frequency of 50Hz, what would their output frequencies be respectively?





Topic: Frequency Output of Rectifiers

Correct Answer: A) 50Hz, 100Hz

Short Hint:
  • Half-wave rectification retains the input frequency, which is 50Hz in this case.
  • Full-wave rectification effectively doubles the output frequency, making it 100Hz.
  • So, the correct answer is A, "50Hz, 100Hz".

Question 9:

What is one of the main functions of a diode in an electronic circuit?





Topic: Roles of Diodes in Electronic Circuits

Correct Answer: C) Rectification

Short Hint:
  • A diode's primary function is to allow current to flow in one direction, enabling rectification (conversion of AC to DC).
  • It achieves this by allowing only one half of the AC waveform to pass through.
  • Therefore, the correct answer is C, "Rectification".

Question 10:

What is the power efficiency of a half-wave rectifier?





Topic: Rectifier Efficiency

Correct Answer: C) 40.6%

Short Hint:
  • The efficiency of a rectifier relates to its ability to convert AC to DC.
  • For a half-wave rectifier, this efficiency is 40.6%.
  • This is because it only uses half of the input wave, leading to a lot of power wastage.
  • Hence, the correct answer is C, "40.6%".

Question 11:

For a half-wave rectifier with an input frequency of 100Hz, what would be the frequency of the ripple?





Topic: Half-Wave Rectifier Frequency

Correct Answer: C) 100Hz

Detailed Hint:
  • A half-wave rectifier operates by only allowing one half of an AC waveform to pass through to the output.
  • Therefore, the frequency of the ripple, or the repeating pattern observed in the output, is identical to the input frequency.
  • In this instance, with an input frequency of 100Hz, the ripple frequency is also 100Hz.
  • Hence, the correct answer is C, "100Hz."

Question 12:

In relation to a P-N junction diode that is not connected to any circuit, which statement is true?





Topic: P-N Junction Diode

Correct Answer: C) An electric field exists at the junction, pointing from the N-type side to the P-type side.

Detailed Hint:
  • A P-N junction diode, even when not connected to a circuit, maintains an electric field.
  • This electric field is created due to the difference in charge carriers between the P-type and N-type materials that form the diode.
  • The field direction is from the negatively charged N-type side towards the positively charged P-type side.
  • Therefore, the correct answer is C, "An electric field exists at the junction, pointing from the N-type side to the P-type side."

MCQs 13:

Which of the following best describes the function of a diode?





Topic: Diode Function

Correct Answer: D) None of the above.

Detailed Hint:
  • Diodes have a variety of applications, but they are most commonly used as rectifiers.
  • A rectifier is a type of circuit that converts alternating current (AC) into direct current (DC).
  • This function of a diode is not reflected in options A, B, or C.
  • As a result, the correct answer is D, "None of the above."

MCQs 14:

What is the primary application of a PN junction diode?





Topic: PN Junction Diode

Correct Answer: A) As a rectifier.

Detailed Hint:
  • The PN junction diode is a versatile electronic component with various applications.
  • Its main function, however, is to serve as a rectifier.
  • Rectifiers are used to convert alternating current (AC) into direct current (DC).
  • Therefore, the correct answer is A, "As a rectifier."

MCQs 15:

What is the efficiency of a center tapped full-wave rectifier?





Topic: Rectifier Efficiency

Correct Answer: D) 81.2%

Detailed Hint:
  • Rectifier efficiency is a measure of its effectiveness in converting AC to DC.
  • This is calculated by taking the ratio of the DC power output to the maximum AC power delivered to the load, and is usually expressed as a percentage.
  • For center tapped full-wave rectifiers, this efficiency is 81.2%.
  • Hence, the correct answer is D, "81.2%."

MCQ 16:

What type of rectifier uses 2 diodes?





Topic: Rectifiers

Correct Answer: C) Full-wave rectifier.

Detailed Hint:
  • The type of rectifier is determined by the number of diodes it uses and how they are configured.
  • A full-wave rectifier requires at least 2 diodes.
  • These diodes are arranged in such a way that when one diode is forward-biased, the other is reverse-biased.
  • As a result, the correct answer is C, "Full-wave rectifier."

MCQ 17:

What is the peak inverse voltage on a diode given a peak voltage of 5V on a center-tapped full-wave rectifier circuit and a diode cut-in voltage of 0.7V?





Topic: Diode Characteristics - Peak Inverse Voltage

Correct Answer: B) 9.3V

Detailed Hint:
  • Peak inverse voltage (PIV) in a rectifier is a crucial parameter, which signifies the maximum negative voltage a diode can withstand.
  • It is typically calculated as PIV = 2Vm - Vd.
  • Here, Vm is the peak voltage (5V in this case) and Vd is the diode cut-in voltage (0.7V here).
  • By substituting the given values into the equation, we obtain PIV = 9.3V.
  • Thus, the correct answer is B, "9.3V."

MCQ 18:

What is the average output direct current value in a half-wave rectifier?





Topic: Half-Wave Rectifier - Average Output Current

Correct Answer: A) Io/π

Detailed Hint:
  • In a half-wave rectifier, the average output direct current is a key quantity.
  • It is defined as the average value of current over a cycle divided by 2.
  • Mathematically, it can be represented as (2Io/2π).
  • Simplifying the above expression, we get Io/π.
  • Therefore, the correct answer is A, "Io/π."

MCQs 19:

For which type of rectifier can a bridge rectifier serve as a substitute?





Topic: Rectifiers

Correct Answer: A) Full wave rectifier

Detailed Hint:
  • A bridge rectifier is a particular type of rectifier that uses four diodes in a bridge arrangement to achieve full-wave rectification.
  • It is considered superior to a full-wave rectifier due to its ability to convert both halves of an AC waveform to pulsating DC.
  • Therefore, a bridge rectifier is an excellent alternative for a full-wave rectifier.
  • Hence, the correct answer is A, "Full wave rectifier."

MCQs 20:

What would be the ripple frequency of a full-wave rectifier if the input frequency is 50Hz?





Topic: Full-Wave Rectification

Correct Answer: A) 100Hz

Detailed Hint:
  • Ripple frequency is an important aspect of a full-wave rectifier, as it directly relates to the consistency of the rectified output.
  • It is generally double the input frequency in a full-wave rectifier.
  • Given that the input frequency in this scenario is 50Hz, the ripple frequency will be 2 * 50Hz = 100Hz.
  • Therefore, the correct answer is A, "100Hz."

MCQs 21:

What effect does half-wave rectification have on the frequency of a wave?





Topic: Rectification and Wave Frequency

Correct Answer: D) Remains same

Detailed Hint:
  • Half-wave rectification implies the conversion of one-half of the input AC signal into a DC signal.
  • It does not modify the frequency of the wave; rather, it maintains the same frequency as the input signal.
  • Full rectification, on the other hand, doubles the frequency.
  • As such, the correct response is D, "Remains same."

MCQs 22:

Under what conditions does a P-N junction diode perform as an insulator?





Topic: P-N Junction Diode

Correct Answer: C) When reverse-biased

Detailed Hint:
  • The behavior of a P-N junction diode depends on its biasing condition.
  • When the diode is forward-biased, it conducts current, acting as a conductor.
  • However, when the diode is reverse-biased, it blocks current flow, thus acting as an insulator.
  • Therefore, the correct answer is C, "When reverse-biased."

MCQs 23:

In a full-wave rectifier, how is the biasing of the two diodes set at a given instance?





Topic: Full-Wave Rectifier

Correct Answer: A) One is forward-biased while the other is reverse-biased

Detailed Hint:
  • In a full-wave rectifier circuit, two diodes are used to convert the entire input signal into a DC output.
  • The diodes are set up such that when one is in a forward-biased state, the other is in a reverse-biased state.
  • This configuration ensures the conversion of both halves of the AC input into DC output.
  • Therefore, the correct answer is A, "One is forward-biased while the other is reverse-biased."

MCQs 24:

What is the transformer utilization factor for a center-tapped full-wave rectifier?





Topic: Transformer Utilization Factor (TUF)

Correct Answer: C) 0.693

Detailed Hint:
  • The transformer utilization factor (TUF) is a measure of how effectively a transformer is used by a rectifier.
  • It is defined as the ratio of the AC power delivered to the load to the DC power rating of the transformer.
  • For a center-tapped full-wave rectifier, the TUF is typically around 0.693.
  • Therefore, the correct answer is C, "0.693."