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MCQs 1

What leads to the production of positive rays?





Topic: Generation of Positive Rays

Correct Answer: C) By ionizing the gas

Detailed Hint:
  • Positive rays, also known as canal rays, are generated in a gas discharge tube.
  • The process starts when cathode rays (electron streams) collide with gas molecules in the tube.
  • This collision ionizes the gas, meaning it ejects electrons from the gas molecules.
  • This results in the production of positive ions or positive rays.
  • Therefore, the correct answer is C, "By ionizing the gas".

MCQs 2

What are the potential m values for l ≥ 1 in quantum mechanics?





Topic: Quantum Numbers and Their Significance

Correct Answer: C) -1, 0, +1

Detailed Hint:
  • In quantum mechanics, the magnetic quantum number (m) represents the possible orientations of the orbital in space.
  • For a given azimuthal quantum number (l), the magnetic quantum number (m) can take values from -l to +l including 0.
  • Therefore, for l ≥ 1, the possible m values can be -1, 0, and +1.
  • Hence, the correct answer is C, "-1, 0, +1".

Question 3:

Which electron configuration corresponds to the highest energy level?





Topic: Energy Levels and Electron Configuration

Correct Answer: A) N 3, l 2, m 0, s +1/2

Detailed Hint:
  • In electron configuration, the principal quantum number (N) represents the energy level of an electron.
  • The larger the value of N, the higher the potential energy of the electron.
  • However, if the N value is the same, then the energy depends on the azimuthal quantum number (l).
  • Therefore, among the given options, the electron with configuration N 3, l 2, m 0, s +1/2 has the highest energy.
  • Hence, the correct answer is A, "N 3, l 2, m 0, s +1/2".

Question 4:

Which gas has the maximum e/m ratio in positive rays?





Topic: Positive Rays and Gas Properties

Correct Answer: A) Hydrogen

Detailed Hint:
  • The e/m value, or the charge-to-mass ratio, for positive rays is dependent on the mass of the gas used in the gas discharge tube.
  • The lighter the mass of the gas, the higher the e/m value.
  • Among the given options, hydrogen has the least mass.
  • Therefore, the e/m value for positive rays is maximum for hydrogen.
  • Hence, the correct answer is A, "Hydrogen".

Question 5:

What is the correct electron configuration of Manganese?





Topic: Electron Configuration of Elements

Correct Answer: A) 3d5, 4s2

Detailed Hint:
  • The electron configuration describes how electrons are distributed in the atomic orbitals of an atom.
  • Manganese, which is the 25th element on the periodic table, has an electron configuration of 3d5, 4s2.
  • Therefore, the correct answer is A, "3d5, 4s2".

Question 6:

How many electrons can an f-sub shell orbital accommodate at maximum?





Topic: Electron Capacity of Atomic Orbitals

Correct Answer: A) 2

Detailed Hint:
  • Every orbital in any sub-shell can accommodate a maximum of 2 electrons only.
  • This includes the f-sub shell orbital.
  • Thus, the correct answer is A, "2".

Question 7:

Which quantum number gives information about the orientation of orbitals?





Topic: Quantum Numbers and Orbital Orientation

Correct Answer: D) Magnetic quantum number

Detailed Hint:
  • The quantum numbers define the state of an electron within an atom.
  • The magnetic quantum number is the one that tells us about the orientation of an orbital within a subshell.
  • It can have values from -l to +l (including 0), where l is the azimuthal quantum number.
  • Thus, the correct answer is D, "Magnetic quantum number".

MCQs 8:

What is the total number of unpaired electrons in an atom with the electron configuration 1s2, 2s2, 2p4?





Topic: Electron Configuration and Unpaired Electrons

Correct Answer: B) 2

Detailed Hint:
  • The electron configuration 1s2, 2s2, 2p4 indicates there are 2 unpaired electrons in the 2p orbital.
  • This is because the 2p orbital can accommodate up to 6 electrons, and it currently has only 4.
  • Thus, the correct answer is B, "2".

MCQs 9:

As the value of the principal quantum number ‘n’ increases, what happens to the size of the ‘s’ orbital?





Topic: Orbital Size with Quantum Number

Correct Answer: A) Increase

Detailed Hint:
  • The principal quantum number 'n' is directly proportional to the size of the 's' orbital.
  • Therefore, as the value of 'n' increases, the size of the 's' orbital also increases.
  • Hence, the correct answer is A, "Increase".

MCQs 10:

Where is there a 95% probability of locating an electron in the space around the nucleus?





Topic: Electron Probability and Atomic Orbitals

Correct Answer: C) Atomic orbital

Detailed Hint:
  • The atomic orbital is described as the volume of space in which there is a 95% chance of finding an electron.
  • An electron's highest probability of being found is at a distance of 0.053nm.
  • Therefore, the correct answer is C, "Atomic orbital".

MCQs 11:

What do we call the orbitals that possess identical energy?





Topic: Energy Equivalence in Orbitals

Correct Answer: C) Degenerate orbitals

Detailed Hint:
  • The term used for orbitals of the same energy level is "degenerate orbitals".
  • This term is applied irrespective of the type of orbital.
  • Therefore, the correct answer is C, "Degenerate orbitals".

MCQs 12:

What determines the characteristics of anode rays?





Topic: Impact on Positive Ray Properties

Correct Answer: B) The nature of gas in the discharge tube

Detailed Hint:
  • The e/m ratio of the particle in anode rays is dependent on the nature of the gas in the discharge tube.
  • As the mass (nature) of the gas changes, the e/m value also fluctuates.
  • Thus, the correct answer is B, "The nature of gas in the discharge tube".

MCQs 13:

Which quantum number provides information about the energy level of an electron within an atom?





Topic: Quantum Numbers and Electron Energy

Correct Answer: A) Principal

Detailed Hint:
  • The principal quantum number (n) is responsible for providing information about the energy level of an electron in an atom.
  • It is also incorporated in the energy formula derived by Bohr.
  • Hence, the correct answer is A, "Principal".

Question 14:

How would you accurately illustrate the cross and dot structure of Chlorine atoms?





Topic: Cross and Dot Diagrams

Correct Answer: B) Option B

Detailed Hint:
  • The cross and dot diagram represents an atom's electron arrangement.
  • In the case of Chlorine, option B gives the correct representation.
  • Therefore, the correct answer is B, "Option B".

Question 15:

Compared to the first orbit, how much further is the third orbit of a hydrogen atom from the nucleus?





Topic: Orbital Distances in Hydrogen Atom

Correct Answer: C) Nine times

Short Hint:
  • The distance of an orbit from the nucleus can be calculated using the formula 0.529n2Ao.
  • For the first orbit, it will be 0.529(1)^2Ao = 0.529 Ao, and for the third orbit, it will be 0.529(3)^2Ao = 0.529 × 9 Ao.
  • Hence, the correct answer is C, "Nine times".

Question 16:

In which type of orbitals would you find five degenerate orbitals?





Topic: Degenerate Orbitals and Types

Correct Answer: C) d-orbital

Short Hint:
  • Degenerate orbitals refer to orbitals that have the same energy level.
  • Five degenerate orbitals are particularly found in d-orbitals.
  • Thus, the correct answer is C, "d-orbital".

MCQs 17:

How many unpaired electrons are there in a ground state Nickel atom? (Atomic number of Ni is 28)





Topic: Unpaired Electrons in Nickel Atom

Correct Answer: A) 2

Detailed Hint:
  • The atomic number of Nickel (Ni) is 28, and its electronic configuration is 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸ 4s².
  • By evaluating the outer configuration, we can notice that there are two unpaired electrons.
  • Consequently, the correct answer is A, "2".

MCQs 18:

What is the angular momentum of the second orbit?





Topic: Angular Momentum in Orbits

Correct Answer: A) h/π

Detailed Hint:
  • The formula for angular momentum is given by nh/2π where 'n' is the orbit number.
  • Substituting 'n' with 2 in the formula, we get h/π.
  • Therefore, the correct answer is A, "h/π".

MCQs 19:

Which orbital diagram illustrates a violation of the Aufbau principle?





Topic: Violations of the Aufbau Principle

Correct Answer: B) Option B

Detailed Hint:
  • The Aufbau principle states that electrons fill up orbitals in order of increasing energy, starting with s-subshell as it has the lower energy level.
  • Option B shows a violation of this principle, with the p-subshell being filled before the s-subshell.
  • Hence, the correct answer is B, "Option B".

MCQs 20:

Which one of the electrons listed below possesses the most substantial energy?





Topic: Electron Energy Levels

Correct Answer: A) N 3, l 2, m 0, s +1/2

Detailed Hint:
  • The energy of an electron is determined by the principal quantum number 'n', as well as the azimuthal quantum number 'l'.
  • With the highest combined values of 'n' and 'l', option A holds the electron with the most energy.
  • Thus, the correct answer is A, "N 3, l 2, m 0, s +1/2".

MCQs 21:

What is the ratio between the radii of the second and third Bohr orbits for a hydrogen atom?





Topic: Radii of Bohr Orbits in Hydrogen Atom

Correct Answer: C) 4:9

Detailed Hint:
  • The radius of an orbit can be calculated using the formula 0.529n^2Ao, where 'n' is the orbit number.
  • Substituting 'n' with 2 for the second orbit, and 3 for the third orbit, we get 0.529(2)^2Ao and 0.529(3)^2Ao.
  • Consequently, the correct answer is C, "4:9".

Question 22:

For which of the following species is Bohr's theory not applicable?





Topic: Limitations of Bohr's Theory

Correct Answer: C) He2+

Detailed Hint:
  • Bohr's theory applies to species containing one electron and not for species having no electron at all.
  • Helium 2+ is an example of such a species, as it does not contain any electron.
  • Hence, the correct answer is C, "He2+".
  • The other species listed do contain electrons, and thus Bohr's theory is applicable to them.

Question 23:

The charge of one gram of electron is:





Topic: Charge Carried by Electrons

Correct Answer: C) 1.7588 × 108

Detailed Hint:
  • Since an electron’s mass is 9.109×10-28 g, this means there are about 1/(9.11×10-28) 1.098×1027 electrons present in a gram.
  • Given that the charge of one electron is 1.602×10-19 C, we can compute the charge in a gram of electrons: (1.098×1027) (1.602×10-19) C 1.759×108 C.
  • Therefore, the correct answer is C, "1.7588 × 108".

Question 24:

Choose the isoelectronic pair.





Topic: Isoelectronic Species

Correct Answer: C) Ar & Ca2+

Detailed Hint:
  • Isoelectronic species are those which have an equal number of electrons.
  • Argon (Ar) and Calcium 2+ (Ca2+) both have 18 electrons, making them isoelectronic.
  • Hence, the correct answer is C, "Ar & Ca2+".

Question 25:

When the 5d orbital is complete, the entering electron goes into





Topic: Electron Orbital Filling Order

Correct Answer: D) 6p

Detailed Hint:
  • The electron filling order for orbitals is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, etc.
  • After the 5d orbital has been filled up, the next orbital to be filled is the 6p orbital.
  • Therefore, the correct answer is D, "6p".

Question 26:

Maximum number of electrons in M–shell is?





Topic: Atomic Structure - Electrons and Shells

Correct Answer: C) 18

Short Hint:
  • The maximum number of electrons in a shell is given by the formula 2n2.
  • Where n is the principal quantum number.
  • For the M-shell, n is 3.
  • Therefore, the maximum number of electrons in the M-shell is 2*32 = 18.

Question 27:

The velocity of photon is:





Topic: Waves - Nature of Light

Correct Answer: A) Independent of its wavelength

Short Hint:
  • The velocity of light is constant, regardless of its wavelength or source.
  • This is why all light travels at the same speed, approximately 300,000 kilometers per second in a vacuum.

Question 28:

Which sub-shell is represented by the quantum numbers n4 and l3?





Topic: Quantum Numbers and Sub-Shell Identification

Correct Answer: D) 4f

Short Hint:
  • The quantum number `l` is used to denote sub-shells: `s` (when `l=0`), `p` (when `l=1`), `d` (when `l=2`), and `f` (when `l=3`).
  • Given `n=4` and `l=3`, we find that the sub-shell is `4f`.

Question 29:

The correct electronic configuration notation for Neon (Ne) is?





Topic: Electronic Configuration

Correct Answer: D) 1s2, 2s2, 2p6

Short Hint:
  • The electronic configuration notation for an atom tells us the distribution of its electrons in different orbitals.
  • According to the Aufbau principle, electrons fill up orbitals in order of increasing energy.
  • The order of filling of orbitals is as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, and so on.
  • Neon has an atomic number of 10, which means that it has 10 electrons.
  • The first two electrons in neon fill up the 1s orbital. The next two electrons fill up the 2s orbital. The remaining six electrons fill up the 2p orbital.
  • Therefore, the correct electronic configuration notation for neon is 1s2, 2s2, 2p6.

MCQs 30:

What are the quantum number values for 2p orbitals?





Topic: Quantum Numbers for 2p Orbitals

Correct Answer: A) n 2, l 1

Detailed Hint:
  • The principal quantum number in a 2p orbital is 2, thus n = 2.
  • For a p orbital, the azimuthal quantum number (l) is 1.
  • Therefore, for a 2p orbital, the quantum numbers are n = 2, l = 1.

MCQs 31:

Where is the probability of detecting an electron zero between two orbitals?





Topic: Zero Probability Regions for Electrons

Correct Answer: C) Nodal surface

Detailed Hint:
  • In quantum mechanics, certain regions show zero probability of finding an electron.
  • These regions, termed nodal surfaces, lie between orbitals.

MCQs 32:

Which orbital possesses zero radial nodes?





Topic: Radial Nodes in Orbitals

Correct Answer: D) 4f

Detailed Hint:
  • The number of radial nodes in an orbital can be calculated using the formula: Radial nodes = n – l – 1.
  • For a 4f orbital, using the formula gives: 4 – 3 – 1 = 0.
  • This means a 4f orbital has no radial nodes.

MCQs 34:

Which quantum number determines the shape of an orbital?





Topic: Shapes of Orbitals and Quantum Numbers

Correct Answer: B) l

Detailed Hint:
  • The shape of an orbital is defined by the azimuthal quantum number, denoted as 'l'.
  • It characterizes the orbital angular momentum.

MCQs 35:

What is the correct term for the quantum number symbolized by "n"?





Topic: Quantum Number Naming Convention

Correct Answer: A) Principal quantum

Detailed Hint:
  • In quantum physics, each quantum number has a designated symbol and name for identification.
  • The quantum number symbolized by 'n' is known as the Principal quantum number.
  • Therefore, the correct answer is A, "Principal quantum".

MCQs 36:

Which quantum number is known as the 'Principal quantum number'?





Topic: Principal Quantum Number

Correct Answer: A) The quantum number symbolized by 'n'

Detailed Hint:
  • The Principal quantum number, symbolized by 'n', is one of the four quantum numbers in quantum mechanics.
  • It determines the energy of an electron in an atom and the size of the orbital it occupies.
  • Therefore, the correct answer is A, "The quantum number symbolized by 'n'".

MCQs 37:

What is the name of the quantum number represented by the symbol 'n'?





Topic: Understanding Quantum Numbers

Correct Answer: D) Principal quantum number

Detailed Hint:
  • In quantum mechanics, quantum numbers are used to describe the unique state of a particle, such as an electron in an atom.
  • The quantum number symbolized by 'n' is known as the Principal quantum number which determines the energy level and size of the orbital.
  • Hence, the correct answer is D, "Principal quantum number".